Optimal. Leaf size=335 \[ \frac {i \sqrt {2} \sqrt {a} \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}-\frac {i \sqrt {2} \sqrt {a} \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}-\frac {i \sqrt {a} \log \left (a \sqrt {e}-\sqrt {2} \sqrt {a} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))\right )}{\sqrt {2} d \sqrt {e}}+\frac {i \sqrt {a} \log \left (a \sqrt {e}+\sqrt {2} \sqrt {a} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))\right )}{\sqrt {2} d \sqrt {e}} \]
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Rubi [A]
time = 0.16, antiderivative size = 335, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 7, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.233, Rules used = {3594, 303,
1176, 631, 210, 1179, 642} \begin {gather*} \frac {i \sqrt {2} \sqrt {a} \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {a+i a \tan (c+d x)} \sqrt {e \cos (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}-\frac {i \sqrt {2} \sqrt {a} \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {a+i a \tan (c+d x)} \sqrt {e \cos (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}-\frac {i \sqrt {a} \log \left (-\sqrt {2} \sqrt {a} \sqrt {a+i a \tan (c+d x)} \sqrt {e \cos (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))+a \sqrt {e}\right )}{\sqrt {2} d \sqrt {e}}+\frac {i \sqrt {a} \log \left (\sqrt {2} \sqrt {a} \sqrt {a+i a \tan (c+d x)} \sqrt {e \cos (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))+a \sqrt {e}\right )}{\sqrt {2} d \sqrt {e}} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 303
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 3594
Rubi steps
\begin {align*} \int \frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {e \cos (c+d x)}} \, dx &=-\frac {(4 i a) \text {Subst}\left (\int \frac {x^2}{a^2 e^2+x^4} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{d}\\ &=\frac {(2 i a) \text {Subst}\left (\int \frac {a e-x^2}{a^2 e^2+x^4} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{d}-\frac {(2 i a) \text {Subst}\left (\int \frac {a e+x^2}{a^2 e^2+x^4} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{d}\\ &=-\frac {(i a) \text {Subst}\left (\int \frac {1}{a e-\sqrt {2} \sqrt {a} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{d}-\frac {(i a) \text {Subst}\left (\int \frac {1}{a e+\sqrt {2} \sqrt {a} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{d}-\frac {\left (i \sqrt {a}\right ) \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {a} \sqrt {e}+2 x}{-a e-\sqrt {2} \sqrt {a} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e}}-\frac {\left (i \sqrt {a}\right ) \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {a} \sqrt {e}-2 x}{-a e+\sqrt {2} \sqrt {a} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}\right )}{\sqrt {2} d \sqrt {e}}\\ &=-\frac {i \sqrt {a} \log \left (a \sqrt {e}-\sqrt {2} \sqrt {a} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))\right )}{\sqrt {2} d \sqrt {e}}+\frac {i \sqrt {a} \log \left (a \sqrt {e}+\sqrt {2} \sqrt {a} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))\right )}{\sqrt {2} d \sqrt {e}}-\frac {\left (i \sqrt {2} \sqrt {a}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}+\frac {\left (i \sqrt {2} \sqrt {a}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}\\ &=\frac {i \sqrt {2} \sqrt {a} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}-\frac {i \sqrt {2} \sqrt {a} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}}{\sqrt {a} \sqrt {e}}\right )}{d \sqrt {e}}-\frac {i \sqrt {a} \log \left (a \sqrt {e}-\sqrt {2} \sqrt {a} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))\right )}{\sqrt {2} d \sqrt {e}}+\frac {i \sqrt {a} \log \left (a \sqrt {e}+\sqrt {2} \sqrt {a} \sqrt {e \cos (c+d x)} \sqrt {a+i a \tan (c+d x)}+\sqrt {e} \cos (c+d x) (a+i a \tan (c+d x))\right )}{\sqrt {2} d \sqrt {e}}\\ \end {align*}
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Mathematica [A]
time = 0.96, size = 125, normalized size = 0.37 \begin {gather*} \frac {i e^{-\frac {3}{2} i d x} \left (-e^{-2 i c}\right )^{3/4} \left (1+e^{2 i (c+d x)}\right ) \left (\text {ArcTan}\left (\frac {e^{\frac {i d x}{2}}}{\sqrt [4]{-e^{-2 i c}}}\right )-\tanh ^{-1}\left (\frac {e^{\frac {i d x}{2}}}{\sqrt [4]{-e^{-2 i c}}}\right )\right ) \sqrt {a+i a \tan (c+d x)}}{d \sqrt {e \cos (c+d x)}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 1.48, size = 225, normalized size = 0.67
method | result | size |
default | \(-\frac {\left (i \sin \left (d x +c \right )-\cos \left (d x +c \right )+1\right ) \left (1+\cos \left (d x +c \right )\right ) \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \sqrt {e \cos \left (d x +c \right )}\, \left (i \arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1+\sin \left (d x +c \right )\right )}{2}\right )-i \arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1-\sin \left (d x +c \right )\right )}{2}\right )-\arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1+\sin \left (d x +c \right )\right )}{2}\right )-\arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1-\sin \left (d x +c \right )\right )}{2}\right )\right ) \sqrt {\frac {a \left (i \sin \left (d x +c \right )+\cos \left (d x +c \right )\right )}{\cos \left (d x +c \right )}}}{2 d e \sin \left (d x +c \right )}\) | \(225\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Both result and optimal contain complex but leaf count of result is larger than
twice the leaf count of optimal. 1399 vs. \(2 (229) = 458\).
time = 0.67, size = 1399, normalized size = 4.18 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 301, normalized size = 0.90 \begin {gather*} -\frac {1}{2} \, \sqrt {\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} \log \left (\sqrt {2} \sqrt {\frac {1}{2}} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1} e^{\left (-\frac {1}{2} i \, d x - \frac {1}{2} i \, c\right )} + \frac {1}{2} i \, d \sqrt {\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} e^{\frac {1}{2}}\right ) + \frac {1}{2} \, \sqrt {\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} \log \left (\sqrt {2} \sqrt {\frac {1}{2}} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1} e^{\left (-\frac {1}{2} i \, d x - \frac {1}{2} i \, c\right )} - \frac {1}{2} i \, d \sqrt {\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} e^{\frac {1}{2}}\right ) - \frac {1}{2} \, \sqrt {-\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} \log \left (\sqrt {2} \sqrt {\frac {1}{2}} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1} e^{\left (-\frac {1}{2} i \, d x - \frac {1}{2} i \, c\right )} + \frac {1}{2} i \, d \sqrt {-\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} e^{\frac {1}{2}}\right ) + \frac {1}{2} \, \sqrt {-\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} \log \left (\sqrt {2} \sqrt {\frac {1}{2}} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1} e^{\left (-\frac {1}{2} i \, d x - \frac {1}{2} i \, c\right )} - \frac {1}{2} i \, d \sqrt {-\frac {4 i \, a e^{\left (-1\right )}}{d^{2}}} e^{\frac {1}{2}}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {i a \left (\tan {\left (c + d x \right )} - i\right )}}{\sqrt {e \cos {\left (c + d x \right )}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\sqrt {a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}}{\sqrt {e\,\cos \left (c+d\,x\right )}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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